If q = .4, what is the frequency of homozygous recessive individuals?
A. 0.4
B. 0.16
C. 2(.4)
D. (.4)
E. 0.6
Answer: B (0.16)
Explanation:
According to the Hardy-Weinberg principle, if q = 0.4, then we all know that p = 0.6, because p + q = 1.
[p (0.6) + q (0.4)] = 1
From the above question, if q represents the frequency of a homozygous recessive allele (a), then the frequency of homozygous recessive genotype (aa) will be q2 or (0.4)2 = 0.16. And, the frequency (p) of homozygous dominant genotype (AA) will be p2 or (0.6)2 = 0.36. While, the frequency (2pq) of heterozygous dominant genotype (Aa) will be 2pq or 2 × (0.6) × (0.4) = 0.48.
If there are 100 people, then the frequency of homozygous recessive (aa), homologous dominant (AA), and heterozygous dominant (Aa) organisms will be 16, 36, and 48 members, respectively.
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